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7.9.2 map()

7.9.2 map()

The map()method passes each element of the array on which it is invoked to the function you specify, and returns an array containing the values returned by that function. For example:

a = [1, 2, 3]; b = { return x*x; }); // b is [1, 4, 9]

The function you pass to map() is invoked in the same way as a function passed to forEach(). For the map()method, however, the function you pass should return a value. Note that map() returns a new array: it does not modify the array it is invoked on. If that array is sparse, the returned array will be sparse in the same way: it will have the same length and the same missing elements.

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