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4.12.1 eval()

4.12.1 eval()


eval()expects one argument. If you pass any value other than a string, it simply returns that value. If you pass a string, it attempts to parse the string as JavaScript code, throwing a SyntaxError if it fails. If it successfully parses the string, then it evaluates the code and returns the value of the last expression or statement in the string or undefined if the last expression or statement had no value. If the string throws an exception, the eval() propagates that expression.

The key thing about eval() (when invoked like this) is that it uses the variable environment of the code that calls it. That is, it looks up the values of variables and defines new variables and functions in the same way that local code does. If a function defines a local variable x and then calls eval("x"), it will obtain the value of the local variable. If it calls eval("x=1"), it changes the value of the local variable. And if the function calls eval("var y = 3;"), it has declared a new local variable y. Similarly a function can declare a local function with code like this:

eval("function f() { return x+1; }");

If you call eval() from top-level code, it operates on global variables and global functions, of course.

Note that the string of code you pass to eval()must make syntactic sense on its own— you cannot use it to paste code fragments into a function. It makes no sense to write eval("return;"), for example, because return is only legal within functions, and the fact that the evaluated string uses the same variable environment as the calling function does not make it part of that function. If your string would make sense as a standalone script (even a very short one like x=0 ), it is legal to pass to eval(). Otherwise eval() will throw a SyntaxError.

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